Vintage Electronics

Copper ion react with what to form visible formation ???

I need to do an experiment with copper ion. I need to know is there any copper ion in my experiment oil. In order to know, I need to add something that will react with copper ion (if present) and form visible formation or changes in colour. By observing the changes, I can assume that the oil contained copper ion qualitatively. The question is…I dont know what to add to see the reaction. Could someone help me..

Reduction of Cu2+ ions with and without I? as a ligand was studied in N2-purged alcoholic solutions by pulse radiolysis. In the absence of iodide ion, the initial rate constant for e?sol reaction with Cu2+ was determined following the decay of solvated electrons in different alcohols; kbimol values are in the range of 0.8–1.1×1010 dm3 mol?1 s?1. In the presence of 10?3 mol dm?3 KI, the respective kbimol remained almost same. Generally, on reduction, Cu(II) ion changes to Cu(I) ion initially and later it produces metallic copper (Cu°), and the stability of these intermediates depends on the conditions of the matrix. In the presence of I?, Copper ions such as Cu(II) or Cu(I) ions get reduced to metallic copper (Cu°) having initial absorption around 740 and below 400 nm. Later, at 100 ?s time after the electron pulse, it gets transformed into a nanoparticle with an absorption band at 580 nm. Such formation of copper nanoparticle was observed only in 2-propanolic medium in the presence of iodide ions. During ?-radiolysis of N2-purged 1.5×10?4 CuSO4 solutions in 2-propanol, reddish pink colored copper nanoparticles were formed, which are quite similar to those reported earlier in aqueous solution. But, in the presence of I? (2-propanolic solutions), such phenomenon was not noticed on ?-radiolysis. Interestingly, the formation of copper nanoparticle was observed also in the reactions of copper (II) ions with alcohol radicals formed during ?-radiolysis in N2O-purged system, where e?sol were scavenged by N2O. The nanoparticles generated both in N2 and N2O-purged alcoholic systems, viz. methanol, ethanol and 2-propanol, were found to be oxygen sensitive. The contradictory results from pulse and ?-radiolysis studies in the presence and absence of iodide ions are explained to account for the nanoparticle generation.?